Friday, September 16, 2011
How to become a certified basketball official in Massachusetts? Any info?
I am interested in becoming a basketball official on the side. I am really looking to just do Adult League games and things like that rather then High School. Basically, I need to do them in the evenings. Any suggestions would be appreciated.|||games.
What shirts look good with basketball shorts?
I like to wear shirts from like pacsun or american eagle with basketball shorts. But I don't really play sports, I just like them. I don't really like the way cargo shorts look though. Would this combination look good together?|||with basketball shorts you can wear alot of things with it, a wide variety of colors.. but you have to make sure it looks ok.
you said you like pacsun and american eagle? so do i.
but things you could wear with basketball shorts are t-shirts basically; for example:
-http://www.ae.com/web/browse/product.jsp鈥?/a> %26lt;--this T comes in many different colors and can be mix matched with basketball shorts.
-http://shop.pacsun.com/girls/tees/Frozen鈥?/a> %26lt;--this is a simple white with colors on the back that can be matched with colored basketball shirts.
these t-shirts are comfortable and can go with basketball shorts because they are simple, nothing with buttons.. or zippers... should be worn with them because that would not look good.
glad i could help,
ask anytime!
-daphne|||Yes they would - I also suggest loose t-shirts.|||Yeah, thats like the perfect combination!
I know exactly what ur talkin about. I do the same thing and love it! :]|||hmmm how bout a school mascot shirt. idk|||a t-shirt or a tight fitting tank top look good !
you said you like pacsun and american eagle? so do i.
but things you could wear with basketball shorts are t-shirts basically; for example:
-http://www.ae.com/web/browse/product.jsp鈥?/a> %26lt;--this T comes in many different colors and can be mix matched with basketball shorts.
-http://shop.pacsun.com/girls/tees/Frozen鈥?/a> %26lt;--this is a simple white with colors on the back that can be matched with colored basketball shirts.
these t-shirts are comfortable and can go with basketball shorts because they are simple, nothing with buttons.. or zippers... should be worn with them because that would not look good.
glad i could help,
ask anytime!
-daphne|||Yes they would - I also suggest loose t-shirts.|||Yeah, thats like the perfect combination!
I know exactly what ur talkin about. I do the same thing and love it! :]|||hmmm how bout a school mascot shirt. idk|||a t-shirt or a tight fitting tank top look good !
How many ways can seven basketball players of different heights line up ?
In how many ways can seven basketball players of different heights line up in a single row so that no
player is standing between two people taller than he is?
Please show how you arrived at answer.|||It is 64, and this is easily shown by induction. (No combinitorics or long proofs are necessary!)
{The number of ways for k players is 2^(k-1) }
Each time a new player enters the line, the number of ways to line them up doubles.
Let n(k) be the number of ways for k players.
We can assume without loss of generality that the (k+1)st player is taller than all the others.
n(k+1) = 2n(k), since for each of the n(k) ways, we can place the (k+1)st player in one of only two places, namely immediately next to the kth (tallest) player on either side of him. If placed anywhere else, there will be at least one player between two taller players.
Since n(1) = 1, n(2) = 2, n(3) = 4, etc,
n(7) = 2^6 = 64|||did everybody miss the "no player is standing between two people taller than he is" part of the question?
**********
the answer's 64. i've got two methods to do it.
method 1 (the user-friendly idiot-proof method)
picture seven individual platforms in a row for the players to stand on (this's what i pictured anyway :p) these are the seven platforms:
A B C D E F G
now assume the players are of height 1ft, 2ft, 3ft, 4ft, 5ft, 6ft, 7ft. actually, honestly speaking, i don't really remember the last time i saw a 1-footer, 2-footer or 3-footer playing basketball, but we can ignore that i guess.
let's also assume that they go up the platforms in ascending height order, i.e. 1-ft goes up first, then 2-ft, then 3-ft... so they don't all rush to choose their favorite platforms at the same time and create chaos. note that this assumption does NOT change the outcome of the question in any way.
now take a look at Mr. 1-foot, where can he stand? he's only got two choices: A or G. if he stands anywhere from B to F he'd be sandwiched by taller guys, 'cause he's the shortest, this should be pretty obvious.
so from this observation we discover a general rule: the shortest shrimp (no offense to the vertically-challenged) ALWAYS stands on one of the far ends of the line.
case 1:
now say 1-ft chooses to go to platform A, so we're left with B~G unoccupied. who's the shortest among the 6 now? none other than Mr. 2-feet. so according to that rule thingy we discovered, he can only stand on B or G.
case 2:
similarly, if 1-ft chooses to go to platform G, we're left with A~F unoccupied, and so 2-ft can only go to A or F.
so 1-ft has 2 choices, and for each choice he makes, 2-ft has 2 choices too, and for each choice 2-ft makes, 3-ft will have 2 choices too, and so on and so forth.
here's a little catch: when we reach 6-ft, he has 2 choices too. after he makes his choice, 7-ft does NOT have a choice, he'd be forced to take that last unoccupied platform.
so it's 2*2*2*2*2*2 = 2^6 = 64
the first 2 represents the number of choices 1-ft can make
the 2nd 2 represents the number of choices 2-ft can make
...
the 6th 2 represents the number of choices 6-ft can make
7-ft has no choice to make so there's only one possibility, but multiplying by 1 is stupid so we'll ignore it.
i'll try my best to create a tree diagram to explain this if you still have trouble understanding.
......................................鈥?br>
.................................___A_鈥?choices
...........................__B__...._G鈥?choices
..........................C.......G...鈥?choices
...
the underscores are the branches to the letters below it.
method 2 (the "cheating" method):
think of it this way: rewrite the whole question, but change 7 players into 1 player, i.e. how many ways can 1 player line up so that he is not sandwiched by taller players, it's a stupid question that comes with the answer 1. duh, there's only ONE way to arrange 1 player - he stands alone.
now try 2 players: 2 players can't sandwich each other - you need 3 to form a "sandwich", so the only arrangements are (1,2) and (2,1), so the answer is 2 different arrangements.
now 3 players: there's only one requirement - 1-ft can't stand in the middle, so (1,2,3), (1,3,2), (2,3,1), and (3,2,1) are possible arrangements, thus there are 4 arrangements.
4 players: remember the "shortest guy must stand on ends" rule? (1,2,3,4) (1,2,4,3) (1,3,4,2) (1,4,3,2) (2,3,4,1) (2,4,3,1) (3,4,2,1) (3,4,1,2) - a grand total of 8 combinations.
you can try 5 if you want, but i find it inconvenient to type 16 combinations here, with 5 numbers each, so yeah.
notice a pattern?
1 player --%26gt; 1 arrangement
2 players --%26gt; 2 arrangements
3 players --%26gt; 4 arrangements
4 players --%26gt; 8 arrangements
can you guess the next?
5 players --%26gt; 16 arrangements
6 players --%26gt; 32 arrangements
7 players --%26gt; 64 arrangements!
and we've got it. to put it more mathematically:
(n) number of players gives 2^(n-1) arrangements.
**********
oh no, i don't know why my tree diagram looks like that, sorry about that.|||this is fairly simple stats:
7 * 6 * 5 * 4 * 3 * 2 * 1 = 5040 ways
you have the first space were you can choose 7 or the 7 players to stand there
the second space you now only have 6 of the 7 players who can stand there
the third spot 5 of 7 and so forth
to add in standing between two people taller than him...i don't totally know if we have enough information about that, because then one of the players (the shortest would always have to be at one of the ends......so then we would have to keep those spots fixed...however the shortest guy has two spots he could be at.)|||5040 ways|||This is my second try:
The total # of arrangements that satisfy the requirement of nobody between two taller players is:
64
there are 7 positions for the tallest player. If he is on either end the other playres must line up by height so there is 1 way each. 2 positions * 1 way = 2.
If the tallest is 1 position in from the end there are 6 players who can be on the short end and the others must be in line so there are 6 ways each. 2 ways to be one 1 * 6 = 12
If the tallest is 2 positions in there are 6*5/2*1 = 15 ways to select 2 players on the short end, in height order. 2 ways to be 2 in * 15 = 30.
If the tallest player is in the middle position there are
6*5*4/3*2*1 = 20 ways to arrange the other 6 around him
in height order = 20.
Answer = 2 + 12 + 20 + 30 = 64 arrangements.
Whew!|||5040
player is standing between two people taller than he is?
Please show how you arrived at answer.|||It is 64, and this is easily shown by induction. (No combinitorics or long proofs are necessary!)
{The number of ways for k players is 2^(k-1) }
Each time a new player enters the line, the number of ways to line them up doubles.
Let n(k) be the number of ways for k players.
We can assume without loss of generality that the (k+1)st player is taller than all the others.
n(k+1) = 2n(k), since for each of the n(k) ways, we can place the (k+1)st player in one of only two places, namely immediately next to the kth (tallest) player on either side of him. If placed anywhere else, there will be at least one player between two taller players.
Since n(1) = 1, n(2) = 2, n(3) = 4, etc,
n(7) = 2^6 = 64|||did everybody miss the "no player is standing between two people taller than he is" part of the question?
**********
the answer's 64. i've got two methods to do it.
method 1 (the user-friendly idiot-proof method)
picture seven individual platforms in a row for the players to stand on (this's what i pictured anyway :p) these are the seven platforms:
A B C D E F G
now assume the players are of height 1ft, 2ft, 3ft, 4ft, 5ft, 6ft, 7ft. actually, honestly speaking, i don't really remember the last time i saw a 1-footer, 2-footer or 3-footer playing basketball, but we can ignore that i guess.
let's also assume that they go up the platforms in ascending height order, i.e. 1-ft goes up first, then 2-ft, then 3-ft... so they don't all rush to choose their favorite platforms at the same time and create chaos. note that this assumption does NOT change the outcome of the question in any way.
now take a look at Mr. 1-foot, where can he stand? he's only got two choices: A or G. if he stands anywhere from B to F he'd be sandwiched by taller guys, 'cause he's the shortest, this should be pretty obvious.
so from this observation we discover a general rule: the shortest shrimp (no offense to the vertically-challenged) ALWAYS stands on one of the far ends of the line.
case 1:
now say 1-ft chooses to go to platform A, so we're left with B~G unoccupied. who's the shortest among the 6 now? none other than Mr. 2-feet. so according to that rule thingy we discovered, he can only stand on B or G.
case 2:
similarly, if 1-ft chooses to go to platform G, we're left with A~F unoccupied, and so 2-ft can only go to A or F.
so 1-ft has 2 choices, and for each choice he makes, 2-ft has 2 choices too, and for each choice 2-ft makes, 3-ft will have 2 choices too, and so on and so forth.
here's a little catch: when we reach 6-ft, he has 2 choices too. after he makes his choice, 7-ft does NOT have a choice, he'd be forced to take that last unoccupied platform.
so it's 2*2*2*2*2*2 = 2^6 = 64
the first 2 represents the number of choices 1-ft can make
the 2nd 2 represents the number of choices 2-ft can make
...
the 6th 2 represents the number of choices 6-ft can make
7-ft has no choice to make so there's only one possibility, but multiplying by 1 is stupid so we'll ignore it.
i'll try my best to create a tree diagram to explain this if you still have trouble understanding.
......................................鈥?br>
.................................___A_鈥?choices
...........................__B__...._G鈥?choices
..........................C.......G...鈥?choices
...
the underscores are the branches to the letters below it.
method 2 (the "cheating" method):
think of it this way: rewrite the whole question, but change 7 players into 1 player, i.e. how many ways can 1 player line up so that he is not sandwiched by taller players, it's a stupid question that comes with the answer 1. duh, there's only ONE way to arrange 1 player - he stands alone.
now try 2 players: 2 players can't sandwich each other - you need 3 to form a "sandwich", so the only arrangements are (1,2) and (2,1), so the answer is 2 different arrangements.
now 3 players: there's only one requirement - 1-ft can't stand in the middle, so (1,2,3), (1,3,2), (2,3,1), and (3,2,1) are possible arrangements, thus there are 4 arrangements.
4 players: remember the "shortest guy must stand on ends" rule? (1,2,3,4) (1,2,4,3) (1,3,4,2) (1,4,3,2) (2,3,4,1) (2,4,3,1) (3,4,2,1) (3,4,1,2) - a grand total of 8 combinations.
you can try 5 if you want, but i find it inconvenient to type 16 combinations here, with 5 numbers each, so yeah.
notice a pattern?
1 player --%26gt; 1 arrangement
2 players --%26gt; 2 arrangements
3 players --%26gt; 4 arrangements
4 players --%26gt; 8 arrangements
can you guess the next?
5 players --%26gt; 16 arrangements
6 players --%26gt; 32 arrangements
7 players --%26gt; 64 arrangements!
and we've got it. to put it more mathematically:
(n) number of players gives 2^(n-1) arrangements.
**********
oh no, i don't know why my tree diagram looks like that, sorry about that.|||this is fairly simple stats:
7 * 6 * 5 * 4 * 3 * 2 * 1 = 5040 ways
you have the first space were you can choose 7 or the 7 players to stand there
the second space you now only have 6 of the 7 players who can stand there
the third spot 5 of 7 and so forth
to add in standing between two people taller than him...i don't totally know if we have enough information about that, because then one of the players (the shortest would always have to be at one of the ends......so then we would have to keep those spots fixed...however the shortest guy has two spots he could be at.)|||5040 ways|||This is my second try:
The total # of arrangements that satisfy the requirement of nobody between two taller players is:
64
there are 7 positions for the tallest player. If he is on either end the other playres must line up by height so there is 1 way each. 2 positions * 1 way = 2.
If the tallest is 1 position in from the end there are 6 players who can be on the short end and the others must be in line so there are 6 ways each. 2 ways to be one 1 * 6 = 12
If the tallest is 2 positions in there are 6*5/2*1 = 15 ways to select 2 players on the short end, in height order. 2 ways to be 2 in * 15 = 30.
If the tallest player is in the middle position there are
6*5*4/3*2*1 = 20 ways to arrange the other 6 around him
in height order = 20.
Answer = 2 + 12 + 20 + 30 = 64 arrangements.
Whew!|||5040
Where can I find good basketball classes for teens in the Bay Area?
I'm looking for an after school program anywhere in the bay area for me to improve my basketball skills, so that I can make varsity next year. Can anyone help?|||Just practice on your own you dont need classes. Just go to a park or gym and shoot jumpers to improve your jumpshot.
You can also take two balls at a time to improve your dribbling skills and work out to improve you stamina and physical conditioning.
You dont need a class to get better at basketball, you have to want it and work hard on your own|||You don't need classes, just have a style and think you CAN NEVER MISS%26gt;|||where do u mean bay area im in texas so im confused maybe at a junior college, check online n maybe ull find something|||check out ur local rec center/YMCA
You can also take two balls at a time to improve your dribbling skills and work out to improve you stamina and physical conditioning.
You dont need a class to get better at basketball, you have to want it and work hard on your own|||You don't need classes, just have a style and think you CAN NEVER MISS%26gt;|||where do u mean bay area im in texas so im confused maybe at a junior college, check online n maybe ull find something|||check out ur local rec center/YMCA
Question for basketball players. How much would you pay a month for a gym with basketball courts only?
I go to 24 hour fitness often and I would normally have to wait an hour until I can play a game on a weekday night. I just want other people's opinion on how much they would pay to go to a gym with like 8 basketball courts. Please leave your feedback on pros and cons please thanks.|||if i was you i'd just play at a local outdoor b-ball court, since its free :D|||where i live theres a gym u could rent for $20/hour. so i guess thats the most ill pay.
pros: u have a gym to ur self and friends
cons: no pickup games...not able to play against new people
pros: u have a gym to ur self and friends
cons: no pickup games...not able to play against new people
How to read high school basketball sports stats in the newspaper?
In the high school basketball section of the newspaper, I will see players names with 3 numbers next to them. For example, John Smith 1-3-10. I know that the last number stands for points. What do the first two numbers stand for?|||it usually goes assits rebounds points but that verys by newspaper
What is going on in the wrestling and basketball section?
I havent been on since about 5 hours ago and i get on and everyone in the wrestling and basketball section are fighting. I think it's immature. Yes, wrestlings fake and basketball is real but why can't we just say in our own sections?|||Nothin better to do..Keeps me entertained at least.|||I'm neutral, if you go to the basketball section, a lot of the WS users are on there, i'm staying here in the WS of course, i'm not in this lol, your right its immature|||I just wasted 15 points asking everybody whats the point of this. Some idiots started invading the bbs and making racist jokes and shitt. Its so retarded. But hell they aint gone listen. We just gota ignore them.|||Because the Basketball people tought it would be fun to invaded another section so they choose us.But those nerds didn't except us to fight back WWE FT3C(For The 3 Count)!!!!!!|||they probbaly have nothing better to do.|||i just want to find out why everyone watches boys touching each other in underwear for a whole year|||I agree with The Rock v Goldberg, if the people of the both sections kept their comments to themselves we wouldnt be in this MESS!!!!|||if everyone keeps it to themselves it will be fine!|||sounds like the steriods are kicking in.|||they are getting revenge on us for invading there place.
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